Two people of different masses sit on a seesaw. The mass of person 1, [tex]M_1[/tex], is 94 kg, and the mass of person 2, [tex]M_2[/tex], is 44 kg. The distance from person 1 to the pivot, [tex]d_1[/tex], is 0.8 m, and the distance from person 2 to the pivot, [tex]d_2[/tex], is 1.3 m. The mass of the board is negligible.

What is the magnitude of the torque about the pivot due to the gravitational force on person 1?

The torque exerted by a person (with a mass of 94kg) sitting 0.8 meters from the pivot on a seesaw due to the gravitational force is calculated as 735.52 Newton meters.

Explanation:

The question is essentially asking for torque exerted by person 1 on a seesaw. The torque could be calculated using the formula: Torque = Force x Distance. Wherein the 'Force' is the product of person 1's mass and the gravitational constant (g ≈ 9.8 m/s²), and 'Distance' is the distance from the pivot.

So to calculate the Torque: Torque = M₁.g.d₁. Substituting the given values, we get Torque = 94kg x 9.8 m/s² x 0.8m = 735.52 Newton Meters.

In conclusion, the torque exerted by person 1 on the seesaw due to gravitational force is approximately 735.52 Newton Meters.

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