College

Two hockey players are about to collide on the ice. One player has a mass of

70 kg and is traveling at 1.4 m/s north. The other has a mass of 75 kg and is

traveling at 1.0 m/s south. The system consists of the two hockey players.

According to the law of conservation of momentum, what is the total

momentum of the system after they collide? Assume the collision is an

elastic collision.

A. 173 kg.m/s south

B. 23 kg-m/s north

C. 23 kg.m/s south

D. 173 kg.m/s north

Two hockey players are about to collide on the ice One player has a mass of 70 kg and is traveling at 1 4 m

Answer :

Two hockey players are about to collide on the ice, so the total momentum of the system when they collide is 23 kg m/s. Hence, option B is correct.

What is momentum?

The result of a particle's mass and velocity is momentum. It has both magnitude and direction because momentum is a vector quantity. According to Isaac Newton's second law of motion, the force pushing a particle has an equal and opposite effect on the temporal rate at which its momentum changes.

[tex]Momentum (p)= Mass(m)*Velocity(v)[/tex]

The given values according to the question is :

p₁ = p₂

(m × v)₁+ (m × v)₂ = (m × v)₁' + (m × v)₂'

(70 kg × 1.4 m/s) + (75 kg) × (-1.0 m/s) = p₂

(98 kg m/s) + (- 75 kg m/s) = 23 kg m/s North

Therefore, the total momentum after collision is 23 kg m/s North.

To know more about momentum :

https://brainly.com/question/24030570

#SPJ2

Answer:

B. 23 kg*m/s north

Explanation:

p_1 = p_2

(m*v)_1 + (m*v)_2 = (m*v)_1' + (m*v)_2'

(70kg*1.4m/s)+(75kg*-1.0m/s) = p_2

(98kg*m/s)+(-75kg*m/s) = 23kg*m/s north

B. 23 kg*m/s north