High School

The following data represent the commute time (in minutes) [tex]x[/tex] and a score on a well-being survey [tex]y[/tex]. The equation of the least-squares regression line is [tex]y = -0.0445x + 69.6846[/tex], and the standard error of the estimate is 0.4362. Complete parts (a) and (b) below.

Commute Time [tex](x)[/tex]: 25, 35, 45, 55, 70, 92, 125
Well-being Score [tex](y)[/tex]: 69.0, 68.1, 67.2, 66.9, 66.6, 66.2, 63.9

(a) Predict the mean well-being index composite score of all individuals whose commute time is 30 minutes.
[tex]y = 68.35[/tex] (Round to two decimal places as needed.)

(b) Construct a 90% confidence interval for the mean well-being index composite score of all individuals whose commute time is 30 minutes.
Lower Bound = ______
Upper Bound = ______
(Round to two decimal places as needed.)

Answer :

Commute time of 30 minutes is approximately 67.51 to 69.19.

(a) To predict the mean well-being index composite score of individuals with a commute time of 30 minutes, we can use the equation of the least-squares regression line. Plugging in x = 30 into the equation y = -0.0445x + 69.6846, we get:

y = -0.0445(30) + 69.6846

y = -1.335 + 69.6846

y ≈ 68.35

Therefore, the predicted mean well-being index composite score for individuals with a commute time of 30 minutes is approximately 68.35.

(b) To construct a 90% confidence interval for the mean well-being index composite score of individuals with a commute time of 30 minutes, we need to consider the standard error of the estimate. The standard error of the estimate, denoted as SE, is given as 0.4362.

A confidence interval can be calculated using the formula:

Lower Bound = predicted y - (critical value * SE)

Upper Bound = predicted y + (critical value * SE)

Since we want to construct a 90% confidence interval, we need to find the critical value associated with a 90% confidence level. This critical value can be obtained from statistical tables or software and is typically denoted as t*.

Assuming that our sample size is large enough and follows normal distribution properties, we can use a t-distribution for this calculation.

For a 90% confidence level, with n-2 degrees of freedom (where n is the number of data points), the critical value t* is approximately 1.833.

Plugging in the values into the formula, we get:

Lower Bound = 68.35 - (1.833 * 0.4362)

Upper Bound = 68.35 + (1.833 * 0.4362)

Lower Bound ≈ 67.51

Upper Bound ≈ 69.19

Learn more about mean here:

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