Two forces A and B applied together on object C. Force A has an magnitude of 25.6 and making an angle of 26.5 degrees with respect to positive x axis. Force B has an magnitude of 99.7 and making an angle of 32.2 with respect to negative y axis. What is the magnitude of the net force of A and B on object C?

To find the net force applied on an object by two forces, we need to calculate the components of each force along the x and y axes and sum up these components. The magnitude of the resultant force is then the square root of the sum of the squares of these summed components.

Explanation:

To calculate the net force applied on object C by forces A and B, we have to consider the direction as well as the magnitude of each force. In vector addition, we break each force into its components along the x and y axes, and sum up the components along each axis to get the resultant.

The x and y components of force A are: Ax = 25.6 * cos(26.5) and Ay = 25.6 * sin(26.5). The x and y components of force B are: Bx = 99.7 * sin(32.2) (since the direction is along negative y axis) and By = -99.7 * cos(32.2).

The resultant force will then be the vector sum of these two forces, which can be calculated as the square root of the sum of the squares of the individual components: R = sqrt((Ax+Bx)^2 + (Ay+By)^2). Remember to also calculate the resultant angle using the atan2 function.

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