Answer :
Final answer:
To prepare the TPN, approximately 6.25 mL of 23.4% Sodium Chloride Injection will be required.
Explanation:
To calculate the amount of 23.4% Sodium Chloride Injection needed for the TPN, we need to convert mEq (milliequivalents) of Sodium Chloride in the TPN formula to grams, so that it can be compared with the 23.4% Sodium Chloride solution. According to the formula given, the TPN needs 50 mEq Sodium Chloride.
To convert the 50 mEq to grams, first understand that Sodium Chloride = Na+ + Cl- = 23 + 35.5 = 58.5 g/mole or mg/mMol. So, 50 mEq is equivalent to 50/2 = 25 mMol = 25*58.5 = 1462.5 mg which is approximately 1.4625 grams Sodium Chloride.
Then, to find the volume in milliliters of the 23.4% Sodium Chloride injection, the calculation is as follows: Volume = mass of solute (NaCl) / concentration of solution ((mass of solute / Volume) * 100). Thus, Volume = 1.4625 g / (23.4 g/100mL) = approximately 6.25 mL.
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