Answer :
Let's break down the question about fertilizer analysis to find out each component.
How much fertilizer will you multiply by?
The question provides five bags of fertilizer, each weighing 50 pounds.
To find the total weight these bags, multiply:
[tex]5 \text{ bags} \times 50 \text{ pounds per bag} = 250 \text{ pounds}[/tex]
The correct answer is B. 250.
How many pounds of Nitrogen is present?
The fertilizer analysis is given as 13-0-44.1. Each number in this sequence represents the percentage of Nitrogen (N), Phosphorous (P), and Potassium (K) in the fertilizer.
For Nitrogen (N):
[tex]13\% \text{ of 250 pounds}[/tex]
Calculate this as:
[tex]\frac{13}{100} \times 250 = 32.5 \text{ pounds of Nitrogen}[/tex]
The correct answer is C. 32.5.
How many pounds of Phosphorous is present?
The Phosphorous (P) analysis is 0%, meaning no phosphorous is present in the fertilizer. Therefore:
The correct answer is A. 0.
How many pounds of Potassium is present?
The Potassium (K) content is 44.1%.
Calculate the potassium content as:
[tex]\frac{44.1}{100} \times 250 = 110.25 \text{ pounds of Potassium}[/tex]
Note that usually, Potassium is measured as potash content (K[tex]_2\text{O}[/tex]), but the percentage given directly in the problem must be applied. Therefore:
The correct answer is D. 110.
