The table below shows the times taken for a group of athletes to finish a 200m race.

Work out the percentage of the athletes who took more than 28 seconds to finish the race.

[tex]
\[
\begin{tabular}{|c|c|}
\hline
\text{Time, } t(s) & \text{Frequency} \\
\hline
24 < t \leq 26 & 3 \\
\hline
26 < t \leq 28 & 6 \\
\hline
28 < t \leq 30 & 9 \\
\hline
30 < t \leq 32 & 7 \\
\hline
\end{tabular}
\]
[/tex]

First, we identify the groups of athletes based on their finishing times. The intervals are:

- For times [tex]$24 < t \leq 26$[/tex], there are [tex]$3$[/tex] athletes.
- For times [tex]$26 < t \leq 28$[/tex], there are [tex]$6$[/tex] athletes.
- For times [tex]$28 < t \leq 30$[/tex], there are [tex]$9$[/tex] athletes.
- For times [tex]$30 < t \leq 32$[/tex], there are [tex]$7$[/tex] athletes.

We need to work out the percentage of athletes who took more than [tex]$28$[/tex] seconds to finish the race.

1. Calculate the total number of athletes by summing the frequencies:
[tex]$$
\text{Total athletes} = 3 + 6 + 9 + 7 = 25.
$$[/tex]

2. Identify which athletes took more than [tex]$28$[/tex] seconds. These are the athletes in:
- [tex]$28 < t \leq 30$[/tex] with [tex]$9$[/tex] athletes.
- [tex]$30 < t \leq 32$[/tex] with [tex]$7$[/tex] athletes.

So, the total number of athletes with times greater than [tex]$28$[/tex] s is:
[tex]$$
\text{Athletes over }28\text{ s} = 9 + 7 = 16.
$$[/tex]

3. Calculate the percentage:
[tex]$$
\text{Percentage} = \left(\frac{16}{25}\right) \times 100 = 64\%.
$$[/tex]

Thus, the percentage of athletes who took more than [tex]$28$[/tex] seconds to finish the race is [tex]$64\%$[/tex].