Answer :
I not exactly sure if this is right but with the numbers that you are given, you can do a simple division problem of 91/30=3.0999 because you don't want decimals, you need a solid number of gallons you must buy you would have to buy 4 gallons for that 91 octane mix, leaving you with some gas.
Hope I helped you!
Hope I helped you!
It would need 20 gallons of 93 octane gas.
To create a 91 octane mix using 87 and 93 octane gasoline, we can employ a simple algebra technique known as a weighted average. The goal is to find out how many gallons of 87 octane gas (x) and how many gallons of 93 octane gas (y) you would need to combine to get a total of 30 gallons of 91 octane gas.
The equations that represent this scenario are:
x + y = 30 (the total gallons needed)
87x + 93y = 91 × 30 (representing the final octane level needed)
To solve this, we can use substitution or elimination. Since we already have the first equation set up nicely for substitution with x + y = 30, we can express y as y = 30 - x and substitute it into the second equation.
87x + 93(30 - x) = 2730
By solving for x, we get:
87x + 2790 - 93x = 2730
-6x = -60
x = 10
So, you would need 10 gallons of 87 octane. To find y, substitute 10 for x in the first equation:
y = 30 - 10
y = 20
Therefore, you would need 20 gallons of 93 octane gas.
