Answer :
The radioactive decay of sm-151 (an isotope of samarium) can be modeled by the differential equation dy /dt = -0.0077y, DOthe half-life of Sm-151 is 90 years.
What is sm-151?
Sm-151 is a radioactive isotope of the element Samarium. The symbol for Sm-151 is 151Sm, and the atomic number of Samarium is 62. This isotope has a half-life of 88 years.
Differential equations differential equation that model the radioactive decay of Sm-151 is given as
dy/dt = -0.0077y, where t is measured in years.
To find the half-life of Sm-151, we can use the formula for half-life, which is given as:
t1/2 = (ln 2) / k
Where k is the decay constant. To find k, we can use the given differential equation.
dy/dt = -0.0077y
Separating variables, we get
dy / y = -0.0077 dt
Integrating both sides,
we get ln y = -0.0077 t + C
Where C is the constant of integration.
To find C, we use the initial condition, y(0) = y0, where y0 is the initial amount of Sm-151.
Substituting this in the above equation, we get ln y0 = CSo,
the equation becomes y = -0.0077 t + ln y0
Taking the exponential of both sides, we get y = y0 e^(-0.0077t)
Using the formula for k, we get k = 0.0077
Substituting this in the formula for half-life,
we get: t1/2 = (ln 2) / k
= (ln 2) / 0.0077
= 90 years
Therefore, the half-life of Sm-151 is 90 years.
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