Answer :
Final answer:
The binomial probability formula allows you to calculate the probability of a specific number of successes in a given number of trials. In this case, you can use it to calculate the probability of winning exactly 21 out of 30 games. Use the values n = 30, x = 21, and p = 0.659 in the formula, and always round your final answer to two decimal places.
Explanation:
The subject of this question is probability, specifically the probability of a specific number of successes in a given number of trials. In this case, the 'success' is winning the arcade game, and the 'trial' is playing the game.
The question asks what the probability is of winning exactly 21 times out of 30 plays. In mathematical terms, this is a binomial probability problem.
The formula for binomial probability is P(x; n, p) = C(n, x) * (p^x) * ((1 – p)^(n–x)) where P(x; n, p) represents the probability of getting exactly x wins in n trials, C(n, x) equals the number of combinations of n items taken x at a time, p represents the probability of winning one game, and x and n are the number of wins and the number of games, respectively.
In this problem, n = 30 (the number of games played), x = 21 (the desired number of wins), and p = 0.659 (the probability of winning one game). Plugging these values into the formula gives a value for the probability of winning exactly 21 games.
Due to the complexity of the calculations, it may be best to use a scientific calculator or online calculator capable of binomial probability calculations. Always remember to round your final answer to two decimal places.
Learn more about Binomial Probability here:
https://brainly.com/question/33993983
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The complete question is: The probability of winning on an arcade game is 0.659. If you play the arcade game 30 times, what is the probability of winning exactly 21 times?Round your answer to two decimal places. is:
