High School

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------------------------------------------------ Which equation, when solved, results in a different value of [tex]$x$[/tex] than the other three?

A. [tex]$8.3 = -0.6x + 11.3$[/tex]

B. [tex]$11.3 = 8.3 + 0.6x$[/tex]

C. [tex]$11.3 - 0.6x = 8.3$[/tex]

D. [tex]$8.3 - 0.6x = 11.3$[/tex]

Answer :

Sure! Let's solve each equation step by step to find the value of [tex]\(x\)[/tex].

1. Equation 1: [tex]\(8.3 = -0.6x + 11.3\)[/tex]
- Start by subtracting 11.3 from both sides to isolate terms with [tex]\(x\)[/tex]:
[tex]\[
8.3 - 11.3 = -0.6x
\][/tex]
[tex]\[
-3 = -0.6x
\][/tex]
- Now, divide both sides by [tex]\(-0.6\)[/tex] to solve for [tex]\(x\)[/tex]:
[tex]\[
x = \frac{-3}{-0.6} = 5
\][/tex]

2. Equation 2: [tex]\(11.3 = 8.3 + 0.6x\)[/tex]
- Subtract 8.3 from both sides to get:
[tex]\[
11.3 - 8.3 = 0.6x
\][/tex]
[tex]\[
3 = 0.6x
\][/tex]
- Divide both sides by 0.6 to solve for [tex]\(x\)[/tex]:
[tex]\[
x = \frac{3}{0.6} = 5
\][/tex]

3. Equation 3: [tex]\(11.3 - 0.6x = 8.3\)[/tex]
- Subtract 11.3 from both sides to find terms with [tex]\(x\)[/tex]:
[tex]\[
11.3 - 8.3 = 0.6x
\][/tex]
[tex]\[
-3 = -0.6x
\][/tex]
- Divide both sides by [tex]\(-0.6\)[/tex]:
[tex]\[
x = \frac{-3}{-0.6} = 5
\][/tex]

4. Equation 4: [tex]\(8.3 - 0.6x = 11.3\)[/tex]
- Subtract 8.3 from both sides to bring terms with [tex]\(x\)[/tex] together:
[tex]\[
8.3 - 8.3 - 0.6x = 11.3 - 8.3
\][/tex]
[tex]\[
-0.6x = 3
\][/tex]
- Divide both sides by [tex]\(-0.6\)[/tex]:
[tex]\[
x = \frac{3}{-0.6} = -5
\][/tex]

After comparing the solutions, we find:

- For equations 1, 2, and 3, the value of [tex]\(x\)[/tex] is 5.
- For equation 4, the value of [tex]\(x\)[/tex] is [tex]\(-5\)[/tex].

Thus, equation 4 is the one that results in a different value of [tex]\(x\)[/tex] compared to the others.