Answer :
Final answer:
To find the mass of NO formed in the oxidation of ammonia, balance the equation, calculate the moles of ammonia and oxygen, determine the limiting reactant, and use stoichiometry to find the mass of NO.
Explanation:
To determine the mass of NO that is formed in the oxidation of ammonia, we first need to balance the equation:
4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (g)
Using the given mass of ammonia (46.0 kg) and oxygen (118 kg), we can calculate the number of moles of each:
Moles of NH3 = mass of NH3 / molar mass of NH3
Moles of O2 = mass of O2 / molar mass of O2
Next, we compare the stoichiometry of the balanced equation to determine the limiting reactant. In this case, ammonia is the limiting reactant. Therefore, the number of moles of NO formed is equal to the number of moles of ammonia used. Finally, we can calculate the mass of NO formed:
Mass of NO = moles of NO × molar mass of NO
Mass of NO formed = [moles of NH3 × molar mass of NO] / moles of NH3
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