Answer :
120 = 2L + 2W and L=2W
120 = 2(2W) + 2W = 4W + 2W = 6W
120/6= W
Width = 20”
Length = 2W = 40”
The flag is 20” x 40”.
120 = 2(2W) + 2W = 4W + 2W = 6W
120/6= W
Width = 20”
Length = 2W = 40”
The flag is 20” x 40”.
The dimensions of Jamaican flag are length is equal to 40 inches and width is equal to 20 inches.
It is given that perimeter of Jamaican flag is 120 inches and length is twice the width of flag.
We have to find out the dimensions of the flag.
What is the perimeter of a rectangle ?
The perimeter of a rectangle is equal to 2 times the sum of length and width i.e., P = 2(L + B) where L is length and B is width of rectangle.
As per the question ;
Perimeter of Jamaican flag = 120 inches
Let's assume width be x.
Then ;
Length = 2x
So ;
To find out the dimensions let's use the formula of perimeter which is ;
P = 2(L + B)
⇒ 120 = 2 (x + 2x)
⇒ 120 = 2 × 3x
⇒ 120 = 6x
⇒ x = 120 ÷ 6
⇒ x = 20 inches
⇒ Width = 20 inches
and the length will be ;
= 2 × 20
= 40 inches
Thus , the dimensions of Jamaican flag are length is equal to 40 inches and width is equal to 20 inches.
To learn more about perimeter of a rectangle click here ;
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