College

The perimeter of a rectangle is 120 meters, and the length is 20 meters longer than the width.

Find the dimensions of the rectangle. Let [tex] x [/tex] be the length and [tex] y [/tex] be the width.

The corresponding system of equations is:
\[ 2x + 2y = 120 \]
\[ x - y = 20 \]

Solve the system graphically.

Answer :

The dimension of the rectangle is 40meters by 20meters

What is the perimeter of a figure?

The perimeter of a figure is the sum of all the external sides of the figure

The formula for calculating the perimeter of rectangle = 2(l+w)

If the length is 20 meters longer than the width, then;

l = 20 + w

Substitute

120 = 2(20+2w)

60 = 20 + 2w

30 = 10 + w

w = 20 meters

Since l = 20 + w

l = 20 + 20

l = 40 meters

Hence the dimension of the rectangle is 40meters by 20meters

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