Answer :
The number of groups that can be made from 5 different green balls, 4 different blue balls, and 3 different red balls, including at least 1 green and 1 blue ball, is 3720(Option b).
To find the number of groups, we need to consider the combinations of balls while ensuring at least one green and one blue ball is included.
The number of ways to select at least one green ball from 5 is 2^5 - 1 = 31 (subtracting 1 to exclude the case of no green balls).
The number of ways to select at least one blue ball from 4 is 2^4 - 1 = 15.
The number of ways to select any number of red balls from 3 is 2^3 = 8.
Now, the total number of groups that can be made by including at least one green and one blue ball is:
Total groups = (31) × (15) × (8) = 3720
Therefore, the correct answer is b. 3720.
You can learn more about combinations at
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