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------------------------------------------------ Using any number of cells rated 2 V and 0.8 Ah, draw a battery circuit that can source 6 V at 4 A for 1 hour.

Answer :

To solve this problem, we need to configure a battery using cells that each have a voltage of 2 volts (V) and a capacity of 0.8 ampere-hours (Ah) in such a way that the battery can supply 6 V at 4 amperes (A) for 1 hour.

Here is a step-by-step solution:

1. Determine the Voltage Requirement:
- We need the battery to output 6 V. Since each cell provides 2 V, we need to connect cells in series to increase the voltage.
- To achieve 6 V:
- Number of cells in series = Total Voltage Required / Voltage per Cell
- Number of cells in series = 6 V / 2 V per cell = 3 cells

So, we need 3 cells in series to achieve the 6 V.

2. Determine the Current and Capacity Requirement:
- The battery needs to supply 4 A for 1 hour, which equals a total capacity requirement of 4 Ah.
- Each cell provides 0.8 Ah, so we need to connect cells in parallel to increase the total capacity.
- To achieve 4 Ah:
- Number of parallel strings = Required Capacity (Ah) / Capacity per Cell
- Number of parallel strings = 4 Ah / 0.8 Ah per cell = 5

Thus, for the required capacity, we need 5 parallel sets, each made up of series cells.

3. Calculate the Total Number of Cells:
- The total number of cells will be the product of the number of cells needed in series and the number of parallel strings.
- Total cells = Number of cells in series × Number of parallel strings
- Total cells = 3 cells in series × 5 parallel strings = 15 cells

Therefore, the battery configuration that meets the requirements is having 3 cells in series, and then this series configuration is repeated 5 times in parallel. This results in a total of 15 cells configured to provide 6 V and 4 A for 1 hour.