High School

The manufacturer of a 6 V dry-cell flashlight battery claims that the battery will deliver 15 mA for 52 continuous hours. During this time, the voltage will drop from 6 V to 4 V. Assume the drop in voltage is linear with time.

Part A: How much energy does the battery deliver in this 52-hour interval?

Express your answer to three significant figures and include the appropriate units.

Answer :

Final answer:

The battery delivers 27,360 joules of energy in the 52-hour interval.

Explanation:

To calculate the energy delivered by the battery, we can use the formula:

Energy (in joules) = Power (in watts) * Time (in seconds)

Given that the battery delivers 15 mA for 52 hours, we need to convert the current to amperes and the time to seconds. So,

Current = 15 mA = 15 * 10-3 A

Time = 52 hours = 52 * 60 * 60 seconds

Now, we can calculate the energy:

Energy = 15 * 10-3 A * 52 * 60 * 60 s = 27,360 joules

Therefore, the battery delivers 27,360 joules of energy in the 52-hour interval.

Other Questions