Answer :
Final answer:
In a population in Hardy-Weinberg equilibrium, the allele frequencies of BW and BW75 would remain at the initial frequencies of 60% and 40%, respectively. The frequency of recombinant offspring in a dihybrid cross would not be predicted to be 60% as it generally does not exceed 50% unless there is linkage.
Explanation:
The Hardy-Weinberg principle is a fundamental concept in population genetics that provides a mathematical baseline for studying genetic variation. If a population is in Hardy-Weinberg equilibrium and the initial allele frequencies for BW and BW75 are 60% and 40%, respectively, these frequencies would remain constant from one generation to the next, provided that all the conditions of the equilibrium are met. Therefore, the answer to the question about the ending frequencies of BW and BW75 alleles is that they would remain the same as the initial frequencies, 60% and 40%, respectively. However, the options provided (A to D) are not correct since frequency in the context of genetics is expressed as a proportion, not in hertz (Hz), which is a unit of frequency for cycles per second in physical sciences.
In regards to recombinant offspring frequencies in a dihybrid cross, under independent assortment, the maximum predicted frequency of recombinant offspring is 50%. If linkage occurs (genes are close on the same chromosome and do not assort independently), the observed recombinant frequency could be less than 50%. Thus, 60% recombinant frequency would not normally be predicted; genes would likely display linkage if the frequency were that high. Mutations, including deletions, could affect these outcomes, but they are not typically associated with predictable changes in recombinant frequencies within one generation in a Hardy-Weinberg context.
