Answer :
Final answer:
The length of the rectangle is 32.5 cm, width is 27.5 cm, and the area is 893.75 cm².
Explanation:
To solve the problem, let's denote the width of the rectangle as w and the length as l. According to the question, the length is 5 more than the width, so we can express this as l = w + 5.
The perimeter of a rectangle is calculated by the formula P = 2l + 2w. Given that the perimeter is 120, we can set up the equation 2(w + 5) + 2w = 120. Simplifying this, we get 4w + 10 = 120, and further simplification gives us 4w = 110. Dividing by 4 yields w = 27.5. Thus, the width of the rectangle is 27.5 cm.
Now, we can find the length by adding 5 to the width: l = 27.5 + 5 = 32.5 cm. The area of the rectangle is found by multiplying the length and width, so Area = l × w = 32.5 × 27.5 = 893.75 square centimeters.
The rectangle's dimensions are: Length = 32.5 cm, Width = 27.5 cm, and Area = 893.75 cm².
The length is 50, the width is 20, and the area is 500. Here’s my work:
