Answer :
Answer:
d₂ = 37,5 m
Explanation:
v₁ = 45 km/h = 12,5 m/s
d₁ = 15 m
v₂ = 112,5 km/h = 31,25 m/s
______________
d₂ = ?
We use the simple rule of three:
12,5 m/s ........... 15 m
31,25 m/s .......... x m
[tex]\implies x=\frac{15\times31,25}{12,5}=\frac{468,75}{12,5}=\bf\red{37,5\:m}\\[/tex]
Success! ❀
Final Answer:
The car will skid x = 60 m with locked brakes at 112.5 km/h.
Explanation:
When a car skids with locked brakes, the distance it skids is directly proportional to the square of its speed. This relationship is described by the formula:
x₁/x₂ = (v₁/v₂)²
where x₁ is the initial skidding distance at speed v₁, and x₂ is the skidding distance at speed v₂. In this scenario, we can use the given information to find the new skidding distance at 112.5 km/h (v₂), when the initial skidding distance is 15 m at 45 km/h (x₁ and v₁):
x₁/x₂ = (45 km/h / 112.5 km/h)²
Solving for x₂:
x₂ = (45² / 112.5²) * 15
After calculation, the car will skid approximately 60 m with locked brakes at 112.5 km/h.
This result aligns with the physical principle that higher speeds lead to longer skidding distances due to the increased kinetic energy. It is crucial for drivers to be aware of this relationship and adjust their driving accordingly to ensure safety on the road.
