Answer :
Final answer:
The period of vibration for a lithotriptor with a frequency of 1.23 MHz is 8.13 x 10^-7 seconds, and its angular frequency is 7.72 x 10^6 rad/s.
Explanation:
The frequency of the lithotriptor is given as 1.23 MHz, which is 1.23 x 106 Hz. The period of vibration and the angular frequency can be calculated using the formulas:
- Period (T) = 1/frequency (f)
- Angular Frequency (ω) = 2π * frequency (f)
So, in order to find the period, we divide 1 by the frequency:T = 1/f = 1/(1.23 x 106) = 8.13 x 10-7 seconds.
To find the angular frequency, we multiply the frequency by 2π: ω = 2πf = 2π * (1.23 x 106) = 7.72 x 106 rad/s.
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