The force [tex] F [/tex], in newtons, acting upon an object is the product of the mass of the object, in kilograms [tex] (kg) [/tex], and the acceleration [tex] a [/tex], in meters per second squared [tex] (m/s^2) [/tex], of the object.

Which equation represents the force [tex] F [/tex], in newtons, acting on an object with a mass of 57 kg and an acceleration of [tex] a \, m/s^2 [/tex]?

A. [tex] F = 57a [/tex]
B. [tex] F = 57 + a [/tex]
C. [tex] F = 57 - a [/tex]
D. [tex] F = a - 57 [/tex]

To solve the problem, we need to find the equation that represents the force [tex]\( F \)[/tex], in newtons, acting on an object with a mass of 57 kg and an acceleration of [tex]\( a \)[/tex] meters per second squared [tex]\((m/s^2)\)[/tex].

The basic formula for force is given by Newton's Second Law of Motion, which states:

[tex]\[ F = m \times a \][/tex]

where:
- [tex]\( F \)[/tex] is the force in newtons,
- [tex]\( m \)[/tex] is the mass in kilograms,
- [tex]\( a \)[/tex] is the acceleration in meters per second squared [tex]\((m/s^2)\)[/tex].

Given that the mass [tex]\( m \)[/tex] of the object is 57 kg, we can substitute this value into the formula:

[tex]\[ F = 57 \times a \][/tex]

This equation shows that the force [tex]\( F \)[/tex] depends on the product of 57 and the acceleration [tex]\( a \)[/tex].

Now, let's look at the answer choices:

A) [tex]\( F = 57a \)[/tex]
B) [tex]\( F = 57 + a \)[/tex]
C) [tex]\( F = 57 - a \)[/tex]
D) [tex]\( a - 57 \)[/tex]

Based on our formula [tex]\( F = 57 \times a \)[/tex], the correct choice is:

A) [tex]\( F = 57a \)[/tex]

This equation correctly represents the force acting on the object given the mass and acceleration.