Answer :
4.47 x 10- 4 spook/ L is the value of Kc for the response N2( g) 3H2( g) 2NH3( g) at 181 °C.
Given
the chemical equation N2(g)+3H2(g)↽−−⇀2NH3(g) is Kp=0.0133 at 181 ∘C.
To Find
the value of Kc for the reaction at 181 ∘C.
Solution
In order to determine the value of Kc for the response N2( g) 3H2( g) 2NH3( g) at 181 °C, we can use the relationship between Kp and Kc.
This equation relates Kp with Kc
Kc = Kp( RT) n
where
Partial pressures are used to express Kp, the equilibrium constant.
In molar attention, Kc represents the equilibrium constant.
The gas constant, or R, is0.08206 L atm/ K spook.
The temperature in Kelvin is T.
The stoichiometric measure n is the difference between the aggregate of the gassy products' and gassy reactants' stoichiometric portions.
Then are the data
Δn = ( 2-( 1 3)) = -2
still, we get
If we substitute the values handed.
The formula for 0.0133 is Kc(0.08206 L/ atm/ Kmol *( 181 273) K)- 2.
When we simplify and find Kc, we gain
Kc equals4.47 x 10- 4 spook/L.
thus,4.47 x 10- 4 spook/ L is the value of Kc for the response N2( g) 3H2( g) 2NH3( g) at 181 °C.
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Answer:
Kc is 18.478
Explanation:
Here we want to calculate Kc given Kp
The equation that links both is given as follows;
Kc = Kp/(RT)^Δn
where Kp = 0.0133
R is molar gas constant = 0.0821 L.atm/mol.k
T is temperature in kelvin = 181 + 273 = 454K
Δn is the change in number of moles between products and reactants = 2-4 = -2
Substituting these values, we have;
Kc = 0.0133/(0.0821 * 454)^-2
Kc = 18.478
