Answer :
To find out how many grams of oxygen gas are in 50.0 liters at standard temperature and pressure (STP), we need to use the formula for mass based on density:
[tex]\[ \text{mass} = \text{density} \times \text{volume} \][/tex]
Here's a step-by-step breakdown:
1. Identify the given values:
- Density of oxygen gas at STP = 1.43 grams per liter (g/L)
- Volume of oxygen gas = 50.0 liters (L)
2. Apply the formula:
- Multiply the density by the volume to find the mass.
- [tex]\(\text{mass} = 1.43 \, \text{g/L} \times 50.0 \, \text{L}\)[/tex]
3. Perform the multiplication:
[tex]\[ \text{mass} = 71.5 \, \text{grams} \][/tex]
So, there are 71.5 grams of oxygen gas in 50.0 liters at STP.
[tex]\[ \text{mass} = \text{density} \times \text{volume} \][/tex]
Here's a step-by-step breakdown:
1. Identify the given values:
- Density of oxygen gas at STP = 1.43 grams per liter (g/L)
- Volume of oxygen gas = 50.0 liters (L)
2. Apply the formula:
- Multiply the density by the volume to find the mass.
- [tex]\(\text{mass} = 1.43 \, \text{g/L} \times 50.0 \, \text{L}\)[/tex]
3. Perform the multiplication:
[tex]\[ \text{mass} = 71.5 \, \text{grams} \][/tex]
So, there are 71.5 grams of oxygen gas in 50.0 liters at STP.