The suspended block, E, has a mass of 10 kg for the system to be in a state of equilibrium. This stems from the balance of forces acting on the system, specifically the tension in the cord and the gravitational force.
The problem being asked is a classic equilibrium physics problem, specifically involving pulleys and tension. When a system is in equilibrium, the forces acting on the system are balanced, i.e., they add up to zero. In this scenario, the 10kg block at D is under the influence of gravitational force, exerting a force of 10g (where g=9.8m/s^2), or 98N, downward. It is balanced by the tension in the cord, which should add up to the same magnitude but in the opposite direction.
If d=1.5m, and length of the cord is 4m, it implies there's 2.5m of cord from D to E. The tension will be evenly distributed across the cord's length. This means that the force at block E must also be 98N for the system to be in equilibrium. With the given mass of block E being unknown, we can find it using the formula F = mg, which can be rearranged as m = F/g.
So, m = 98N/9.8m/s^2 = 10 kg. Thus, the mass of the suspended block E must be 10kg for the system to be in equilibrium.
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