The combined SAT scores for the students at a local high school are normally distributed with a mean of 1516 and a standard deviation of 292. The local college requires a minimum score of 1078 for admission. What percentage of students from this school earn scores that satisfy the admission requirement?

\[ P(X > 1078) = \, ? \]

To find the percentage of students from the school that earn scores satisfying the admission requirement, we calculate the z-score for the minimum required score and find the corresponding area under the normal distribution curve.

To find the percentage of students from the school that earn scores satisfying the admission requirement, we need to calculate the area under the normal distribution curve to the right of the score 1078. First, we calculate the z-score for 1078 using the formula: z = (X - mean) / standard deviation. Substituting the values, we get z = (1078 - 1516) / 292 = -1.474. Now, we need to find the area to the right of this z-score using a z-table or a calculator. The area represents the percentage of students with scores that satisfy the admission requirement.

Using a z-table or calculator, the area to the right of -1.474 is approximately 0.0695 or 6.95%. Therefore, approximately 6.95% of the students from this school earn scores that satisfy the admission requirement.

Learn more about percentage here:

https://brainly.com/question/13497310

#SPJ11