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The cables of a trapeze are approximately 3.5 m long. What is the period of an acrobat swinging on this trapeze?

Answer :

Final answer:

The period of an acrobat swinging on a trapeze can be calculated using the simple pendulum formula T = 2π√(L/g). For a trapeze with cables approximately 3.5 m long, the period is roughly 3.76 seconds. This formula accounts for the length of the cables and the acceleration due to gravity.


Explanation:

Calculating the Period of a Trapeze Swing


The period of an acrobat swinging on a trapeze can be modeled as a simple pendulum. The formula to find the period (T) of a simple pendulum is given by:


T = 2π√(L/g)


Where:



  • T = Period of the pendulum

  • L = Length of the pendulum (in this case, the length of the cables, approximately 3.5 m)

  • g = Acceleration due to gravity (approximately 9.81 m/s²)


We can now substitute the values into the formula:



  1. Substituting for L = 3.5 m and g = 9.81 m/s²:


T = 2π√(3.5/9.81)


Calculating the value:



  1. First, calculate 3.5 / 9.81 = 0.3567.

  2. Now take the square root: √0.3567 = 0.5972.

  3. Finally, multiply by 2π: T = 2 3.1416 0.5972 ≈ 3.76 seconds.


Thus, the period of an acrobat swinging on this trapeze is approximately 3.76 seconds.


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