Answer :
Final answer:
The cooling power capacity of the air conditioner is 1.3125 Btu/s. The unit decreases the heat in the laboratory at a rate of 1.3125 Btu/s, but it also increases the temperature at a rate of 0.75 Btu/s due its operation. Therefore, the net effect on the laboratory is a cooling of 0.5625 Btu/s.
Explanation:
The cooling power capacity of an air conditioner can be calculated using the provided data. Since the Coefficient of Performance (COP) equals to the ratio of heat removed to the power input, then COP = Q/W, where Q is the heat removed and W is the power input. Thus, Q = COP * W = 1.75 * 0.75 = 1.3125 Btu/s. This means that the cooling power capacity of the air conditioner is 1.3125 Btu/s.
As for the net effect in the laboratory, the unit would reduce the temperature by removing heat at a rate of 1.3125 Btu/s. However, it would also increase the room's temperature at a rate of 0.75 Btu/s due to the heat produced by its operation. Thus, the net cooling effect on the laboratory would be 1.3125 - 0.75 = 0.5625 Btu/s.
Learn more about Air Conditioning here:
https://brainly.com/question/33575737
#SPJ11