Answer :
The work done by the brakes is given as
[tex]$$
W = 240\,000 \text{ Joules}.
$$[/tex]
When the brakes are applied, the car travels a distance of
[tex]$$
d = 40 \text{ meters}.
$$[/tex]
We know that work is related to force and distance by the equation
[tex]$$
W = F \cdot d.
$$[/tex]
To find the average force exerted by the brakes, we can rearrange the equation to solve for [tex]$F$[/tex]:
[tex]$$
F = \frac{W}{d}.
$$[/tex]
Substituting the given values, we have
[tex]$$
F = \frac{240\,000}{40}.
$$[/tex]
Calculating the division,
[tex]$$
F = 6000 \text{ Newtons}.
$$[/tex]
Thus, the average force that the brakes exert on the car is
[tex]$$
\boxed{6000 \text{ N}}.
$$[/tex]
[tex]$$
W = 240\,000 \text{ Joules}.
$$[/tex]
When the brakes are applied, the car travels a distance of
[tex]$$
d = 40 \text{ meters}.
$$[/tex]
We know that work is related to force and distance by the equation
[tex]$$
W = F \cdot d.
$$[/tex]
To find the average force exerted by the brakes, we can rearrange the equation to solve for [tex]$F$[/tex]:
[tex]$$
F = \frac{W}{d}.
$$[/tex]
Substituting the given values, we have
[tex]$$
F = \frac{240\,000}{40}.
$$[/tex]
Calculating the division,
[tex]$$
F = 6000 \text{ Newtons}.
$$[/tex]
Thus, the average force that the brakes exert on the car is
[tex]$$
\boxed{6000 \text{ N}}.
$$[/tex]
