High School

Calculate the milli-equivalent of washing soda required to remove hardness from one liter of hard water containing 18.00 mg of Mg²+.

a) 0.9 mEq
b) 1.8 mEq
c) 2.7 mEq
d) 3.6 mEq

Answer :

Final answer:

The milli-equivalent of washing soda required to remove the hardness from the hard water is approximately 1478.29 mEq.

Explanation:

To calculate the milli-equivalent (mEq) of washing soda required to remove the hardness from the water, we need to determine the milli-equivalent of Mg²+ ions in 1 liter of the hard water.

The milli-equivalent of a substance is calculated by dividing the mass of the substance by its equivalent weight. The equivalent weight of Mg²+ ions is equal to its molar mass divided by its valence.

Since the valence of Mg²+ ions is 2 and the molar mass of Mg is 24.31 g/mol, the equivalent weight of Mg²+ is 12.16 g/eq.

Given that the hard water contains 18.00 mg of Mg²+ ions in 1 liter, we can calculate the milli-equivalent of Mg²+ ions as follows:

Milli-equivalent of Mg²+ = (18.00 mg) / (12.16 g/eq) * 1000 = 1478.29 mEq.

Therefore, the milli-equivalent of washing soda required to remove the hardness from one liter of hard water containing 18.00 mg of Mg²+ is approximately 1478.29 mEq.