Answer :
Final answer:
The speed of the water as it leaves the nozzle is calculated as the product of gravity and time, based on the principles of kinematics. Given that the acceleration due to gravity is approximately 9.8m/s² and the time is 2.5 seconds, the result is approximately 24.5 m/s.
Explanation:
To understand and answer the question, we need to apply the law of physics-specifically the principles of kinematics. When the water is shot up vertically from the nozzle, it will keep going up for a while until gravity pulls it back to the ground. The 2.5 seconds you hear the water hitting the ground represents the time it took for the water droplets to ascend and then descend back to the ground. Given that the acceleration of gravity is ~9.8m/s², we can use this and the given time to calculate the initial speed of the water as it leaves the nozzle. The equation we're going to use is:
v = u + a*t
However, because the water is shot up, the initial speed is maximum at the starting point and decreases to zero at the highest point. Thus, the equation becomes:
0 = u - g*t
By rearranging this, we get:
u = g*t
With g = 9.8 m/s² and t = 2.5s, the calculated water speed as it left the nozzle should be around 24.5 m/s.
Learn more about Physics of Fluids here:
https://brainly.com/question/33303897
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