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------------------------------------------------ Suppose the scores of seven members of a women's golf team are [tex]68, 62, 60, 64, 70, 66[/tex], and [tex]72[/tex]. Find the mean, median, and midrange.

A. Mean [tex]= 64[/tex], median [tex]= 64[/tex], midrange [tex]= 64[/tex]
B. Mean [tex]= 65[/tex], median [tex]= 64[/tex], midrange [tex]= 66[/tex]
C. Mean [tex]= 66[/tex], median [tex]= 77[/tex], midrange [tex]= 65[/tex]
D. Mean [tex]= 66[/tex], median [tex]= 66[/tex], midrange [tex]= 66[/tex]

Please select the best answer from the choices provided:
A
B
C
D

To solve the problem, we need to find the mean, median, and midrange of the given golf scores: 68, 62, 60, 64, 70, 66, and 72.

Step 1: Calculate the Mean
- The mean is the average of all the scores.
- To find the mean, add up all the scores and then divide by the number of scores.

[tex]\[ \text{Mean} = \frac{68 + 62 + 60 + 64 + 70 + 66 + 72}{7} \][/tex]

[tex]\[ \text{Mean} = \frac{462}{7} \][/tex]

[tex]\[ \text{Mean} = 66 \][/tex]

Step 2: Calculate the Median
- The median is the middle number when the scores are arranged in ascending order.
- First, order the scores: 60, 62, 64, 66, 68, 70, 72.
- Since there are seven scores (an odd number), the median is the middle score.

The middle score is 66.

Step 3: Calculate the Midrange
- The midrange is the average of the smallest and largest numbers in the set.
- Identify the smallest and largest scores: 60 and 72.

[tex]\[ \text{Midrange} = \frac{60 + 72}{2} \][/tex]

[tex]\[ \text{Midrange} = \frac{132}{2} \][/tex]

[tex]\[ \text{Midrange} = 66 \][/tex]

Based on these calculations, the mean is 66, the median is 66, and the midrange is 66.

Therefore, the correct answer is:
d. Mean [tex]$=66$[/tex], median [tex]$=66$[/tex], midrange [tex]$=66$[/tex]