Answer :
Sure! Let's solve the equation step-by-step:
We start with the equation:
[tex]\[
\log_6 x + \log_6 9 = \log_6 5
\][/tex]
Using the properties of logarithms, we know that:
[tex]\[
\log_b a + \log_b c = \log_b (a \times c)
\][/tex]
So, we can combine the logarithms on the left side:
[tex]\[
\log_6 (x \times 9) = \log_6 5
\][/tex]
Since the logarithms on both sides have the same base, we can equate the arguments (what's inside the logs):
[tex]\[
x \times 9 = 5
\][/tex]
Now, solve for [tex]\( x \)[/tex] by dividing both sides by 9:
[tex]\[
x = \frac{5}{9}
\][/tex]
Therefore, the solution to the equation is:
[tex]\[
x = \frac{5}{9}
\][/tex]
We start with the equation:
[tex]\[
\log_6 x + \log_6 9 = \log_6 5
\][/tex]
Using the properties of logarithms, we know that:
[tex]\[
\log_b a + \log_b c = \log_b (a \times c)
\][/tex]
So, we can combine the logarithms on the left side:
[tex]\[
\log_6 (x \times 9) = \log_6 5
\][/tex]
Since the logarithms on both sides have the same base, we can equate the arguments (what's inside the logs):
[tex]\[
x \times 9 = 5
\][/tex]
Now, solve for [tex]\( x \)[/tex] by dividing both sides by 9:
[tex]\[
x = \frac{5}{9}
\][/tex]
Therefore, the solution to the equation is:
[tex]\[
x = \frac{5}{9}
\][/tex]