Answer :
Answer:
Mass of CaCO3 = 600.54g
Explanation:
The balanced chemical equation for the reaction between CaO and CO2 to form CaCO3 is:
CaO + CO2 → CaCO3
From the balanced equation, we can see that 1 mole of CaO reacts with 1 mole of CO2 to produce 1 mole of CaCO3.
To determine how many grams of CaCO3 will be formed from 6.00 moles of CaO, we need to use the molar mass of CaCO3, which is 100.09 g/mol.
The calculation is as follows:
6.00 moles of CaO × (1 mole of CaCO3 / 1 mole of CaO) × (100.09 g/mol) = 600.54 g
Therefore, 600.54 grams of CaCO3 will be formed from 6.00 moles of CaO.
Mass of CaCO3 = 600.54g
Explanation:
The balanced chemical equation for the reaction between CaO and CO2 to form CaCO3 is:
CaO + CO2 → CaCO3
From the balanced equation, we can see that 1 mole of CaO reacts with 1 mole of CO2 to produce 1 mole of CaCO3.
To determine how many grams of CaCO3 will be formed from 6.00 moles of CaO, we need to use the molar mass of CaCO3, which is 100.09 g/mol.
The calculation is as follows:
6.00 moles of CaO × (1 mole of CaCO3 / 1 mole of CaO) × (100.09 g/mol) = 600.54 g
Therefore, 600.54 grams of CaCO3 will be formed from 6.00 moles of CaO.
600.54 g of CaCO3 would be formed
The chemical equation in balanced form for the reaction between CaO and CO2 to form CaCO3 is
CaO + CO2 -> CaCO3
Here 1 mol of CaO reacts with 1 mol of CO2 to form 1 mol of CaCO3
Therefore 6.00 moles will combine with 6.00 moles of CO2 to form 6.00 moles of CaCO3.
The molar mass of CaCO3= 100.09 g/mol
Number of moles of CaCO3=6.00 moles
we know that,
Number of moles of CaCO3= mass of CaCO3/molar mass of CaCO3
Therefore mass of CaCO3 =Number of moles of CaCO3* molar mass of CaCO3
Mass of CaCO3=6.00moles*100.09g/mol
= 600.54g
To learn more about questions related to chemical equations refer to:
https://brainly.com/question/14562573?
