Answer :
Starting with the equation
[tex]$$
1.53 \, e^t = 39.3,
$$[/tex]
we first isolate the exponential term by dividing both sides by [tex]$1.53$[/tex]:
[tex]$$
e^t = \frac{39.3}{1.53} \approx 25.6863.
$$[/tex]
Next, we take the natural logarithm of both sides to solve for [tex]$t$[/tex]:
[tex]$$
t = \ln\left(25.6863\right) \approx 3.24596.
$$[/tex]
Rounding this value to four decimal places, we obtain
[tex]$$
t \approx 3.246.
$$[/tex]
[tex]$$
1.53 \, e^t = 39.3,
$$[/tex]
we first isolate the exponential term by dividing both sides by [tex]$1.53$[/tex]:
[tex]$$
e^t = \frac{39.3}{1.53} \approx 25.6863.
$$[/tex]
Next, we take the natural logarithm of both sides to solve for [tex]$t$[/tex]:
[tex]$$
t = \ln\left(25.6863\right) \approx 3.24596.
$$[/tex]
Rounding this value to four decimal places, we obtain
[tex]$$
t \approx 3.246.
$$[/tex]
