Answer :
To solve these genetics problems, we need to use Mendelian genetics and Punnett squares. We'll break down each part of the question:
### Part 1: Heterozygous Male Ww x Homozygous Recessive Female ww
1. Parent Genotypes:
- Heterozygous Male: Ww
- Homozygous Recessive Female: ww
2. Construct the Punnett Square:
- Create a grid where one parent's alleles (W and w from Ww) are on the top and the other parent's alleles (both w from ww) are on the side.
```
| W | w |
-------------
w | Ww | ww |
-------------
w | Ww | ww |
```
3. Offspring Genotype Possibilities:
- Ww
- ww
- Ww
- ww
4. Probability of Heterozygous Offspring (Ww):
- Out of the 4 possible outcomes, 2 of them are Ww.
- So, the probability is 2 out of 4, which simplifies to 0.5 or 50%.
### Part 2: Heterozygous Ww x Homozygous Dominant WW
1. Parent Genotypes:
- Heterozygous: Ww
- Homozygous Dominant: WW
2. Construct the Punnett Square:
- Place one parent's alleles on the top (W and w from Ww) and the other parent's alleles on the side (both W from WW).
```
| W | w |
-------------
W | WW | Ww |
-------------
W | WW | Ww |
```
3. Offspring Genotype Possibilities:
- WW
- Ww
- WW
- Ww
4. Probability of Homozygous Recessive Offspring (ww):
- There are no ww genotypes possible from this pair.
- Therefore, the probability is 0 out of 4, or 0%.
So in summary:
- The chance that the offspring will be heterozygous is 50%.
- The probability of having a homozygous recessive offspring is 0%.
### Part 1: Heterozygous Male Ww x Homozygous Recessive Female ww
1. Parent Genotypes:
- Heterozygous Male: Ww
- Homozygous Recessive Female: ww
2. Construct the Punnett Square:
- Create a grid where one parent's alleles (W and w from Ww) are on the top and the other parent's alleles (both w from ww) are on the side.
```
| W | w |
-------------
w | Ww | ww |
-------------
w | Ww | ww |
```
3. Offspring Genotype Possibilities:
- Ww
- ww
- Ww
- ww
4. Probability of Heterozygous Offspring (Ww):
- Out of the 4 possible outcomes, 2 of them are Ww.
- So, the probability is 2 out of 4, which simplifies to 0.5 or 50%.
### Part 2: Heterozygous Ww x Homozygous Dominant WW
1. Parent Genotypes:
- Heterozygous: Ww
- Homozygous Dominant: WW
2. Construct the Punnett Square:
- Place one parent's alleles on the top (W and w from Ww) and the other parent's alleles on the side (both W from WW).
```
| W | w |
-------------
W | WW | Ww |
-------------
W | WW | Ww |
```
3. Offspring Genotype Possibilities:
- WW
- Ww
- WW
- Ww
4. Probability of Homozygous Recessive Offspring (ww):
- There are no ww genotypes possible from this pair.
- Therefore, the probability is 0 out of 4, or 0%.
So in summary:
- The chance that the offspring will be heterozygous is 50%.
- The probability of having a homozygous recessive offspring is 0%.