Answer :
Lethal dose and lethal concentration the lethal dose (LD50) and lethal concentration (LC50) of ethanol are calculated based on the following information:
When the concentration of ethanol in the petri dish was 0.6M, 6 seeds germinated and 14 seeds did not germinate.
The total of seeds in each concentration was 20 seeds.
Therefore, 6/20 = 0.3, and 0.7 did not germinate.
The log concentration of the solution is -0.22.
By calculating the concentration that would kill 50 percent of seeds,
we get LD50 = -0.22 + [(0.5 - 0.3)/(0.7 - 0.3)] x 0.1 = -0.22 + [0.2/0.4] x 0.1 = -0.22 + 0.05 = -0.17M
When the concentration of ethanol in the petri dish was 1.5M, 1 seed germinated and 19 seeds did not germinate.
The total of seeds in each concentration was 20 seeds.
Therefore, 1/20 = 0.05, and 0.95 did not germinate.
The log concentration of the solution is 0.18.
By calculating the concentration that would kill 50 percent of seeds,
we get: LD50 = 0.18 + [(0.5 - 0.05)/(0.95 - 0.05)] x 0.1 = 0.18 + [0.45/0.9] x 0.1 = 0.18 + 0.05 = 0.23M
The LD50 of ethanol is -0.17M
when the concentration of ethanol in the petri dish is 0.6M, and it is 0.23M when the concentration of ethanol in the petri dish is 1.5M.
Since no seed germinated at the concentrations of 2.5M, 5M, and 10M, the lethal concentration (LC50) of ethanol cannot be calculated.
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