Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

2. If the heterozygous Ww is crossed with a homozygous dominant WW, then the probability of having a homozygous recessive offspring is zero.

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Sure! Let's break down the problem step-by-step for both scenarios.

### First Scenario: Ww (heterozygous) x ww (homozygous recessive)

1. Parental Genotypes:
- Male: Ww
- Female: ww

2. Punnett Square:
- The male provides two possible alleles, W or w.
- The female provides two alleles, both w.

```
| | W | w |
|-----|-----|-----|
| w | Ww | ww |
| w | Ww | ww |
```

3. Possible Offspring:
- Ww: Heterozygous
- Ww: Heterozygous
- ww: Homozygous recessive
- ww: Homozygous recessive

4. Probability of Heterozygous Offspring (Ww):
- Out of the 4 possible offspring, 2 are Ww.
- Thus, the probability of having a heterozygous offspring (Ww) is [tex]$ \frac{2}{4} = 0.5 $[/tex].

### Second Scenario: Ww (heterozygous) x WW (homozygous dominant)

1. Parental Genotypes:
- One parent: Ww
- Other parent: WW

2. Punnett Square:
- The first parent provides alleles W or w.
- The second parent provides alleles W and W (both dominant).

```
| | W | w |
|-----|-----|-----|
| W | WW | Ww |
| W | WW | Ww |
```

3. Possible Offspring:
- WW: Homozygous dominant
- Ww: Heterozygous
- WW: Homozygous dominant
- Ww: Heterozygous

4. Probability of Homozygous Recessive Offspring (ww):
- There are no ww offspring as none have two recessive alleles.
- Therefore, the probability of producing a homozygous recessive (ww) offspring is [tex]$ 0.0 $[/tex].

In summary:

- The probability of having a heterozygous offspring (Ww) from the first cross is 0.5.
- The probability of producing a homozygous recessive offspring (ww) from the second cross is 0.0.