Answer :
Let's solve the question step-by-step using Punnett squares to understand the probability of different genotypes for the offspring.
### Scenario 1: Heterozygous Male (Ww) x Homozygous Recessive Female (ww)
1. Identify the Parents' Genotypes:
- Male genotype: Ww (heterozygous)
- Female genotype: ww (homozygous recessive)
2. Set Up the Punnett Square:
- Write the alleles from each parent along the top and side of a 2x2 grid.
```
| W | w |
--------------
w | Ww | ww |
w | Ww | ww |
```
3. Fill in the Punnett Square:
- Combine the alleles from the respective row and column to fill each grid cell.
4. Determine Offspring Genotypes:
- Ww (heterozygous) appears twice.
- ww (homozygous recessive) appears twice.
5. Calculate the Probabilities:
- Probability of heterozygous (Ww) offspring: 2 out of 4 (or 50%).
- Therefore, there is a 50% chance that the offspring will be heterozygous (Ww).
### Scenario 2: Heterozygous (Ww) x Homozygous Dominant (WW)
1. Identify the Parents' Genotypes:
- First parent genotype: Ww (heterozygous)
- Second parent genotype: WW (homozygous dominant)
2. Set Up the Punnett Square:
- Write the alleles from each parent along the top and side of a 2x2 grid.
```
| W | W |
--------------
W | WW | WW |
w | Ww | Ww |
```
3. Fill in the Punnett Square:
- Combine the alleles from the respective row and column to fill each grid cell.
4. Determine Offspring Genotypes:
- WW (homozygous dominant) appears twice.
- Ww (heterozygous) appears twice.
5. Calculate the Probabilities:
- No occurrence of ww (homozygous recessive).
- Thus, the probability of having a homozygous recessive offspring (ww) is 0%.
Therefore, the results are:
- There is a 50% chance of having heterozygous offspring in the first scenario.
- There is a 0% chance of having homozygous recessive offspring in the second scenario.
### Scenario 1: Heterozygous Male (Ww) x Homozygous Recessive Female (ww)
1. Identify the Parents' Genotypes:
- Male genotype: Ww (heterozygous)
- Female genotype: ww (homozygous recessive)
2. Set Up the Punnett Square:
- Write the alleles from each parent along the top and side of a 2x2 grid.
```
| W | w |
--------------
w | Ww | ww |
w | Ww | ww |
```
3. Fill in the Punnett Square:
- Combine the alleles from the respective row and column to fill each grid cell.
4. Determine Offspring Genotypes:
- Ww (heterozygous) appears twice.
- ww (homozygous recessive) appears twice.
5. Calculate the Probabilities:
- Probability of heterozygous (Ww) offspring: 2 out of 4 (or 50%).
- Therefore, there is a 50% chance that the offspring will be heterozygous (Ww).
### Scenario 2: Heterozygous (Ww) x Homozygous Dominant (WW)
1. Identify the Parents' Genotypes:
- First parent genotype: Ww (heterozygous)
- Second parent genotype: WW (homozygous dominant)
2. Set Up the Punnett Square:
- Write the alleles from each parent along the top and side of a 2x2 grid.
```
| W | W |
--------------
W | WW | WW |
w | Ww | Ww |
```
3. Fill in the Punnett Square:
- Combine the alleles from the respective row and column to fill each grid cell.
4. Determine Offspring Genotypes:
- WW (homozygous dominant) appears twice.
- Ww (heterozygous) appears twice.
5. Calculate the Probabilities:
- No occurrence of ww (homozygous recessive).
- Thus, the probability of having a homozygous recessive offspring (ww) is 0%.
Therefore, the results are:
- There is a 50% chance of having heterozygous offspring in the first scenario.
- There is a 0% chance of having homozygous recessive offspring in the second scenario.