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------------------------------------------------ Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that [tex]\(\square\)[/tex] of the offspring will be heterozygous.

[tex]\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\][/tex]

2. If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\(\square\)[/tex].

[tex]\[
\begin{array}{|c|c|c|}
\hline
& W & W \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\][/tex]

Answer :

Let's solve the question step-by-step using Punnett squares to understand the probability of different genotypes for the offspring.

### Scenario 1: Heterozygous Male (Ww) x Homozygous Recessive Female (ww)

1. Identify the Parents' Genotypes:
- Male genotype: Ww (heterozygous)
- Female genotype: ww (homozygous recessive)

2. Set Up the Punnett Square:
- Write the alleles from each parent along the top and side of a 2x2 grid.

```
| W | w |
--------------
w | Ww | ww |
w | Ww | ww |
```

3. Fill in the Punnett Square:
- Combine the alleles from the respective row and column to fill each grid cell.

4. Determine Offspring Genotypes:
- Ww (heterozygous) appears twice.
- ww (homozygous recessive) appears twice.

5. Calculate the Probabilities:
- Probability of heterozygous (Ww) offspring: 2 out of 4 (or 50%).
- Therefore, there is a 50% chance that the offspring will be heterozygous (Ww).

### Scenario 2: Heterozygous (Ww) x Homozygous Dominant (WW)

1. Identify the Parents' Genotypes:
- First parent genotype: Ww (heterozygous)
- Second parent genotype: WW (homozygous dominant)

2. Set Up the Punnett Square:
- Write the alleles from each parent along the top and side of a 2x2 grid.

```
| W | W |
--------------
W | WW | WW |
w | Ww | Ww |
```

3. Fill in the Punnett Square:
- Combine the alleles from the respective row and column to fill each grid cell.

4. Determine Offspring Genotypes:
- WW (homozygous dominant) appears twice.
- Ww (heterozygous) appears twice.

5. Calculate the Probabilities:
- No occurrence of ww (homozygous recessive).

- Thus, the probability of having a homozygous recessive offspring (ww) is 0%.

Therefore, the results are:
- There is a 50% chance of having heterozygous offspring in the first scenario.
- There is a 0% chance of having homozygous recessive offspring in the second scenario.