College

Scientists are preparing two satellites to be launched.

The equation [tex]y = 4600x[/tex] represents the number of miles, [tex]y[/tex], that the satellite, Space Explorer A, flies in [tex]x[/tex] hours.

The table below represents the number of miles, [tex]y[/tex], that the satellite, Space Explorer B, flies in [tex]x[/tex] hours:

\[
\begin{array}{|c|c|}
\hline
\text{Hours (x)} & \text{Miles (y)} \\
\hline
5 & 15000 \\
20 & 60000 \\
22 & 66000 \\
24 & 72000 \\
\hline
\end{array}
\]

How many fewer miles does Space Explorer B travel in one hour than Space Explorer A?

Answer :

Final answer:

Space Explorer B travels 1600 fewer miles in one hour than Space Explorer A. This is calculated by determining that Space Explorer B travels 3000 miles per hour as compared to Space Explorer A's 4600 miles per hour.

Explanation:

To determine how many fewer miles Space Explorer B travels in one hour than Space Explorer A, we first need to find the distance Space Explorer B travels in one hour. According to the table provided in the question, the distance traveled by Space Explorer B in 5 hours is 15,000 miles. We can calculate the hourly distance by dividing this number by 5 hours.

(15,000 miles) / (5 hours) = 3,000 miles per hour for Space Explorer B
Now, using the equation given for Space Explorer A, y = 4600x, we find that Space Explorer A travels 4600 miles in one hour (since x = 1). Therefore, the difference in distance traveled in one hour by the two satellites can be found by subtracting the hourly distance of Space Explorer B from that of Space Explorer A:

(4600 miles for Space Explorer A) - (3000 miles for Space Explorer B) = 1600 miles
Space Explorer B travels 1600 fewer miles in one hour than Space Explorer A.