Answer :
Final answer:
A 1.5 V D-size battery can provide a steady current of approximately 0.55 A for 20 hours before being depleted.
Explanation:
To determine the steady current that a 1.5 V D-size battery can provide for 20 hours before being depleted, we can use the formula:
Energy = Power x Time
In this case, the energy stored in the battery is 60 kJ (60,000 J) and the time is 20 hours (20 x 3600 seconds).
Using the formula, we can rearrange it to find the power:
Power = Energy / Time
Power = 60,000 J / (20 x 3600 s)
Power ≈ 0.83 W
Since Power = Voltage x Current, we can rearrange it to find the current:
Current = Power / Voltage
Current = 0.83 W / 1.5 V
Current ≈ 0.55 A
Therefore, the steady current that this battery can provide for 20 hours is approximately 0.55 A.
