Answer :
Final answer:
The weight of a 95-kilogram man on the moon is 158.65 newtons or about 35.70 pounds. It would require approximately 1.63 gallons to travel 31 miles and approximately 11.05 gallons to travel 210 miles with a truck that gets 19 miles per gallon. The velocity of the skydiver after 4 seconds is approximately 26.19 ft/s and the remaining amount of carbon 14 after 8000 years is approximately 0.35 grams.
Explanation:
To calculate the weight of a 95-kilogram man on the moon, we can use Newton's second law of motion. The force due to gravity on the moon is 1.67 meters per second per second. We can find the weight by multiplying the mass (95 kg) by the acceleration due to gravity on the moon (1.67 m/s/s). So the weight of the man on the moon is 158.65 newtons. To convert this to pounds, we can multiply the weight in newtons by the conversion factor 0.225 pounds/newton, giving us a weight of about 35.70 pounds.
For the truck that gets gas mileage of 19 miles per gallon, we can use the formula g = m/19 to calculate the number of gallons required to travel a certain number of miles. For 31 miles, we divide 31 by 19, giving us approximately 1.63 gallons. For 210 miles, we divide 210 by 19, giving us approximately 11.05 gallons.
To find the velocity of the skydiver after 4 seconds, we can substitute t = 4 into the equation v = 176(1 - 0.834t). Simplifying the equation, we get v = 176(1 - 0.834(4)), which gives us a velocity of approximately 26.19 ft/s.
To determine the amount of carbon 14 remaining after 8000 years, we can use the formula C = 5 * 0.5t/5730. Substituting t = 8000 into the equation, we get C = 5 * 0.5(8000)/5730, which gives us a remaining amount of approximately 0.35 grams.
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