Answer :
A. The total resistance is 19 ohms
B. The current through the 8 ohm resistor is 1.58 A
How to determine the total resistance
- Resistor 1 (R₁) = 6 ohms
- Resistor 2 (R₂) = 5 ohms
- Resistor 3 (R₃) = 8 ohms
- Total resistance (Rₜ) =?
For series connection, the total resistance can be obtained as follow:
Rₜ = R₁ + R₂ + R₃
Rₜ = 6 + 5 + 8
Rₜ = 19 ohms
How to determine the current in the circuit
- Potential difference (V) = 30 V
- Total resistance (R) = 19 ohms
- Current (I) =?
Using ohm's law equation, we obtained the current as follow:
V = IR
Divide both side by R
I = V / R
I = 30 / 19
I = 1.58 A
How to determine the current through 8 ohms
- Total current = 1.58 A
- Resistor (R) = 8 ohms
- Current through 8 ohms =?
From the question given above, we were told that the circuit is in series connection. This simply means that the same current will go through each resistor.
Thus, the current through the 8 ohm resistor will be 1.58 A
Learn more about Ohm's law:
https://brainly.com/question/796939
The total resistance of the circuit is 19 Ω and the current through the 8 ohm resistor is 1.58 A.
In a series circuit with 6 ohm, 5 ohm, and 8 ohm resistors connected to a 30 V battery, the total resistance is 19 ohms, and the current through the 8 ohm resistor is 1.58 A.
In a Series connection, the voltage across each resistor will be different but the current across each of them will be the same.
To find the total resistance in a series circuit, simply add the individual resistances.
For this circuit,
[tex]R_e_q[/tex] = 6 Ω+ 5 Ω + 8 Ω = 19 Ω
Once you have the total resistance, you can use Ohm's Law (V = IR) to find the current.
Given the battery voltage is 30 V, and total resistance is 19 Ω, the current through the 8 ohm resistor will be:
I = V/R = 30V / 19Ω = 1.58 A.
