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MathXL for School: Practice & Problem Solving

1. The coordinates of triangle ABC are given.

a. What is the distance between points A and B?
- Points A and B are _____ units apart.
- (Type an integer, fraction, or mixed number.)

b. Give the coordinates for two points that are 7 units from point C.

(Note: The specific coordinates for points A, B, and C were not provided in the question.)

Answer :

Final answer:

To find the distance between points A and B, we use the distance formula. The coordinates for two points 7 units away from point C can be found by using the distance formula again and solving for the coordinates.

Explanation:

a.

To find the distance between two points, we use the distance formula:

d = √[(x2 - x1)² + (y2 - y1)²]

In this case, the coordinates of point A are (x1, y1) and the coordinates of point B are (x2, y2).

Using the given coordinates of A(-2, -3) and B(8, -9), we can substitute the values into the formula:

d = √[(8 - (-2))² + (-9 - (-3))²]

d = √[10² + (-6)²]

d = √(100 + 36)

d = √136

So, the distance between points A and B is √136 units.

b.

Given that point C has the coordinates (6, -1), we can find two points that are 7 units away from C by using the distance formula again.

Let's call the coordinates of the first point (x, y). Using the distance formula, we have:

d = √[(x - 6)² + (y - (-1))²] = 7

Simplifying this equation gives us:

(x - 6)² + (y + 1)² = 49

We can choose different values for x and solve for y to find various points that are 7 units away from C. For example, if we let x = 0, we get:

(-6)² + (y + 1)² = 49

36 + (y + 1)² = 49

(y + 1)² = 13

y + 1 = √13 or y + 1 = -√13

y = √13 - 1 or y = -√13 - 1

Therefore, two points that are 7 units away from C are (0, √13 - 1) and (0, -√13 - 1).

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