Some $1.50-per-oz spice and some $2.50-per-oz spice are mixed to produce 20 oz of a mixture worth $1.90-per-oz. How many ounces of each should be used?

A. 10 oz of $1.50-per-oz spice and 10 oz of $2.50-per-oz spice
B. 12 oz of $1.50-per-oz spice and 8 oz of $2.50-per-oz spice
C. 8 oz of $1.50-per-oz spice and 12 oz of $2.50-per-oz spice
D. 15 oz of $1.50-per-oz spice and 5 oz of $2.50-per-oz spice

Through the system of equations method, based on the total ounces and total cost of the spices, the solution to the question is 12 oz of $1.50-per-oz spice and 8 oz of $2.50-per-oz spice.

Explanation:

This problem can be solved using the concept of weighted averages or mixture problems in algebra. The question states we have two kinds of spices: a $1.50-per-oz spice and a $2.50-per-oz spice. These are mixed together to create a 20 oz mixture that costs $1.90-per-oz. To find out how many ounces of each spice we should use, we'll set up two equations based on the information given in the question:

The first equation is based on the total ounces of spice. If we assume 'x' denotes the amount of $1.50-per-oz spice and 'y' denotes the amount of $2.50-per-oz spice, then the equation based on total ounces of spice is x + y = 20.
The second equation is based on the total cost of the spice. The equation based on total cost is 1.50*x + 2.50*y = 1.90 * 20.

By solving these two equations, we find that the answer to the question is b) 12 oz of $1.50-per-oz spice and 8 oz of $2.50-per-oz spice.

Learn more about Algebraic solution here:

https://brainly.com/question/29205846

#SPJ11