High School

Mass to Moles

Ammonium carbonate, [tex](NH_4)_2CO_3[/tex], is a fertilizer used to supply both nitrogen and sulfur. How many moles of ammonium carbonate are in 35.8 grams of [tex](NH_4)_2CO_3[/tex]?

_____ mol [tex](NH_4)_2CO_3[/tex]

Answer :

Answer:

0.373 moles of ammonium carbonate

Explanation:

To solve this question we must find the molar mass of ammonium carbonate. With the molar mass and the mass we can find its moles, as follows:

(NH₄)₂CO₃ contains: 2 moles N, 8 moles H, 1 mole C, 3 moles O. Molar mass:

2N = 14.0g/mol*2 = 28.0

8H = 1.0g/mol*8 = 8.0

1C = 12.0g/mol*1 = 12.0

3O = 16.0g/mol*3 = 48.0

Molar mass: 28.0 + 8.0 + 12.0 + 48.0 = 96.0g/mol

The moles of ammonium carbonate in 35.8g are:

35.8g * (1mol / 96.0g) =

0.373 moles of ammonium carbonate

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