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A battery is well insulated while being charged by 12.3 V at a current of 6 A.

Take the battery as a control mass and find:

1. The instantaneous rate of work.
2. The total work done over 4 hours.

Answer :

Final answer:

The instantaneous power or rate of work done on the battery is 73.8 Watts. Over a period of 4 hours, the total work done on the battery is 1062720 Joules.

Explanation:

The subject of this question pertains to the concept of power, work and energy in Physics. When a battery is being charged, work is being done on it in the form of electrical energy.

The instantaneous power or rate of work being done can be calculated using the formula: Power = Voltage x Current. Substituting the given values: Power = 12.3 V x 6 A = 73.8 Watts.

The total work done over a period of time can be calculated using the formula: Energy = Power x Time. Since power has been calculated in Watts (i.e., Joules per second), the time should be in seconds. 4 hours = 14400 seconds. Therefore, the total work done = 73.8 Watts x 14400 seconds = 1062720 Joules.

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