Answer :
Final answer:
About 530.076 kg of quicklime (CaO) can be produced from a metric ton of 94.6% pure limestone through the calcination process, which is the heating of calcium carbonate (CaCO3) to produce CaO and CO2.
Explanation:
The student is asking how much quicklime (CaO) can be produced by heating a metric ton of limestone which contains 94.6% calcium carbonate (CaCO3). To solve this, we need to apply stoichiometry based on the chemical reaction:
CaCO3(s) → CaO(s) + CO2(g)
From the balanced equation, one mole of CaCO3 produces one mole of CaO. Since we have a metric ton (1,000,000 gram) of limestone with 94.6% purity, we first calculate the mass of pure CaCO3:
(1,000,000 g limestone) x (0.946) = 946,000 g of CaCO3
Now, using the molar mass of CaCO3 (100.09 g/mol) and CaO (56.08 g/mol), we can find out how much CaO can be produced:
(946,000 g of CaCO3) / (100.09 g/mol) = 9450 mol of CaCO3
(9450 mol of CaCO3) x (56.08 g/mol of CaO) = 530,076 g of CaO
Therefore, 530,076 g (or 530.076 kg) of quicklime can be prepared from a metric ton of 94.6% pure limestone.
