High School

A boat moves through the water with two

forces acting on it. One is a 2.06×103 N

forward push by the motor, and the other is a

1.78×103 N resistive force due to the water.

What is the acceleration of the 1227.4 kg

boat?

Answer in units of m/s^2

.

Answer :

The boat experiences a net force of 280 N, with a mass of 1227.4 kg. Its acceleration is approximately 0.228 m/s², determined using Newton's second law of motion.

To find the acceleration of the boat, we'll use Newton's second law of motion:

Acceleration (a) = Net Force (Fnet ) / Mass (m).

The motor provides a forward push of 2.06×10³ N (Newtons), while the water exerts a resistive force of 1.78×10³ N.

Now, let's calculate the net force:

Net Force (Fnet ) = Forward Push - Resistive Force

Fnet = 2.06×10³ N - 1.78×10³ N

Fnet = 280 N.

The boat's mass is 1227.4 kg.

Now, we can calculate the acceleration:

a = Fnet / m

a = 280 N / 1227.4 kg

a ≈ 0.228 m/s².

The acceleration of the 1227.4 kg boat is approximately 0.228 m/s².

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