Answer :
The tension in the rope is 288 N.
When an object is hung at the center of the rope, the rope will sag due to the weight of the object. The shape of the rope will be an inverted catenary, which can be approximated as a parabola.
To find the tension in the rope, we can use the following formula for the sag of a rope:
y = (w / 2T) * (L/2)^2
where y is the sag of the rope, w is the weight of the object, T is the tension in the rope, and L is the distance between the supports.
Substituting the given values, we get:
0.371 m = (2380 N / 2T) * (8.74 m / 2)^2
Solving for T, we get:
T = 2 * w / (L^2 * y)T = 2 * 2380 N / (8.74 m)^2 * 0.371 mT = 288 N.
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